Why this calc exists
Bar Bending Schedule (BBS) is the contract document that ties design drawings to procurement. Every kg of steel on site started as a line in a BBS. Get the cutting lengths right and you order exactly what you need. Get them wrong and you're either returning 10 t of offcut or halting a pour while emergency steel is sourced.
IS 2502:1963 (reaffirmed 2021) gives the rules — bend deductions per angle, hook allowances for 90°/135°/180°, plus the 2d-to-12d 'free' straight portion in stirrups. The math is straightforward, but the field habit of quoting 'just add 2d per bend' systematically over-estimates cutting lengths by 5–8 %. The BBS / Cutting Length calculator implements IS 2502 Table VIII exactly and reports the deduction per bend so you can verify each line item.
Code references (with provenance)
- IS 2502:1963 — Code of practice for bending and fixing of bars for concrete reinforcement. Tables VIII (bend deduction) and IX (hook allowance).
- IS 456 Cl 26.2.2.1 — Hooks: 90°/135°/180° bends with straight portion of 4φ/12φ/4φ respectively beyond the bend.
- IS 13920 — Ductile Detailing — seismic 135° hook with 10φ straight (≥ 75 mm) extension for stirrups in seismic zones.
- IS 1786 — High-strength deformed bars (Fe415/500/550/600).
Stirrup cutting length — IS 2502 Table VIII
Closed stirrup (2 hooks at 135°): perimeter = 2(A+E) + 2 cover on each side. For A = 220, E = 370, cover 25 mm, 8 mm bar, two 135° hooks:
perimeter = 2(220 + 370) − 8 × 25 (cover on each side, total 4) = 2 × 590 − 200 = 1180 − 200 = 980 mm.
Hook allowance per IS 2502 Table IX for 135° hook with 12φ straight portion: 12 × 8 + 2 × 8 = 112 mm per hook, × 2 = 224 mm.
Total cut length = 980 + 224 = 1,204 mm for a rectangular stirrup, before any bend deduction.
With bend deductions (Table VIII: 2d for 45°, 2d for 90°, 3d for 135°): for 2 × 90° bends = 2 × 2 × 8 = 32 mm. Final = 1,204 − 32 = 1,172 mm for the rectangular stirrup.
Compare with the simple formula 2(A+E) + 24d = 2(220+370) + 24×8 = 1,180 + 192 = 1,372 mm — that's 17 % over.
Field notes (what trips people up)
- Bend deduction is not hook allowance. Deduction is what gets SHORTER (the bar's curved path is shorter than the straight-line dimension). Allowance is what gets LONGER (the hook projection beyond the bend). Don't confuse them.
- Stirrups in seismic zones (IS 13920 Cl 6.3, hoops per Cl 3.4) need 135° hooks with 10φ straight portion (≥ 75 mm), not 12φ. The calculator's seismic toggle handles this.
- Hook at free end of a longitudinal bar adds 9φ + 9φ = 18φ (90°) or 12φ + 3φ = 15φ (135°) — different from stirrup hook.
- Washer plates at hooks reduce the hook allowance if specified — IS 2502 Table IX notes give plate thicknesses.
Worked example
Site: 25 rectangular stirrups 220 × 370 mm, 8 mm Fe500, normal (non-seismic) zone.
Output: 1,172 mm cut length per stirrup × 25 = 29.3 m total · mass = 29.3 × 0.395 = 11.6 kg · at 1,500 ₹/quintal procurement = ₹174.
FAQ
What's the simplest shortcut for stirrups?
For 8–10 mm bars in non-seismic zones, perimeter + 24d (hook + bend) is a defensible quick estimate. For seismic zones or bars above 12 mm, calculate per bend with IS 2502 Table VIII.
Does the calculator handle crank bars?
Yes — crank (bent-up) bars are 45° bends plus straight legs. The calculator's per-bend deduction handles each 45° as 1d deduction.
Why does IS 2502 give different bend deductions for different bar diameters?
Smaller bars bend tighter (smaller bend radius). IS 2502 Table VIII accounts for this — a 6 mm bar bent 90° has a 1d deduction; a 32 mm bar has a 3d deduction.